> Node B subscribes to node A, and Node C subscribes to Node B, Node A does not
> need to know Node C exists.

I think the second half of that might be incorrect.

Node A still needs to listen to Node C, but it does it through Node B.  I think
you'd still need to do something like this ( 1 = A, 2 = B, 3 = C ) :

store listen ( origin = 3, provider = 2, receiver = 1 );

In trial and error, I have found this to be necessary.

-Dan

Daniel J. Wright                           wright at pair.com
Lead Software Developer, pairNIC   https://www.pairnic.com
pair Networks, Inc.                    http://www.pair.com