On July 26, 2004 09:50 am, Dan Wright wrote:
> > Node B subscribes to node A, and Node C subscribes to Node B, Node A does
> > not need to know Node C exists.
>
> I think the second half of that might be incorrect.
>
> Node A still needs to listen to Node C, but it does it through Node B.  I
> think you'd still need to do something like this ( 1 = A, 2 = B, 3 = C ) :
>
> store listen ( origin = 3, provider = 2, receiver = 1 );
>
> In trial and error, I have found this to be necessary.
Sorry, you are correct, this is what I get for answering email on a monday 
morning before I've had coffee.. 

An example of how to setup the A->B->C replication can be found in 
src/ducttape/test_2_pgbench 


>
> -Dan
>
> Daniel J. Wright                           wright at pair.com
> Lead Software Developer, pairNIC   https://www.pairnic.com
> pair Networks, Inc.                    http://www.pair.com
>
> _______________________________________________
> Slony1-general mailing list
> Slony1-general at gborg.postgresql.org
> http://gborg.postgresql.org/mailman/listinfo/slony1-general

-- 
Darcy Buskermolen
Wavefire Technologies Corp.
ph: 250.717.0200
fx:  250.763.1759
http://www.wavefire.com